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-6p^2+60p=0
a = -6; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-6)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-6}=\frac{-120}{-12} =+10 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-6}=\frac{0}{-12} =0 $
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